jaketodd said:
So what's Einstein's equation for gravitational force?
In General Relativity, the normal way to describe motion in a gravitational field is not using forces but rather using the fact that free-falling objects follow a geodesic in curved space-time. The fact that space-time is curved means that one cannot use it directly as a coordinate system, but instead one has to describe the shape of space in terms of some other coordinate system (in the same way that to create a flat map of a large area of the earth, one has to assume some convention for projecting the actual area to the map).
If you want to map that back to Newtonian terms, the main difference (for "weak field" situations such as in the solar system) is that space is curved and "shrinks" slightly relative to a typical coordinate system which can be applied around a central mass. This adds a term to the force law which depends on the square of the speed.
In the simple case of a dominant central mass with lighter objects moving around it, such as the solar system, the usual practical convention is to use "isotropic" coordinates, in which the speed of light relative to the coordinate system varies slightly with potential but the scale factor at any point is the same for the x, y and z directions. Basically, rulers shrink by (1-Gm/rc
2) and clocks run slow by the same factor, which means that relative to the coordinate system the speed of light is decreased by the square of this factor, approximately (1-2Gm/rc
2).
In that case, the force law for a particle of total energy E moving with momentum
p = E
v/c
2 in a Newtonian gravitational field
g is as follows:
d
p/dt = (E/c
2)
g (1 + v
2/c
2)
You can also divide both sides by the energy to get the following:
d(
v/c
2)/dt = (1/c
2)
g (1 + v
2/c
2)
Note that this is expressed in terms of coordinate values, which differ slightly from local values. In particular, c in the above expression is the coordinate speed of light (which depends on potential), not the local standard value.
This is effectively the same as a special relativity extension of the Newtonian force plus an extra v
2/c
2 term due to the curvature (and scale factor) of space. This means that the rate of change of coordinate momentum for something moving at (or near) the speed of light is twice what Newtonian theory alone would predict.
Note that the above rate of change of momentum does not depend on the direction of travel; it applies regardless of whether the test particle is traveling tangentially, radially or anywhere in between. Also, the rate of change of momentum is directed exactly towards the source (at least in this simplified case where only the central source has a significant mass), which means that angular momentum is conserved too.
For something moving downwards at the speed of light c, it may seem odd that its momentum is increasing, but if you look at the momentum expression Ev/c
2 you will see that for speed of light travel, the momentum is E/c, where E is constant for free fall, but c decreases (slightly) as you get closer to the source. In contrast, the expression for the rate of change of velocity (that is, acceleration) is much more complicated and depends on the direction of travel.