What is the name of this function?

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The function f(x) = x^x does not have a specific name but is related to the concept of 'superexponentiation' or 'tetration.' Tetration is a generalization of exponentiation, represented as {}^n x or x↑↑n, where a number is raised to itself n times. The discussion clarifies that terms like "exponential function" and "power function" are often confused, with the former specifically referring to cases where the variable is in the exponent. The exploration of tetration leads to the study of hyperoperations and very large numbers, such as Graham's Number. Overall, the conversation highlights the complexity and progression of mathematical operations beyond standard exponentiation.
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This is not a problem from a book. It is something I am wondering.

## f(x)=x^a ## is an exponential function
## f(x)=a^x ## is a power function
## f(x)=x ## is a identity function

What is ## f(x)=x^x ## called then?
 
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I don't think there's a special name for it. Since ##x^x=e^{\log x^x}= e^{x\log x}##, it's the composition of an exponential function and the product of the identity function and a logarithm.

Oh, and what you called a power function is an exponential function and vice versa. The term "exponential function" is used when the independent variable (in this case x) is in the exponent.
 
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As Fredrik says, there is no name for that specific one. However, it is a particular case of a more general function called 'superexponentiation' or 'tetration', which is the next step in the chain of generalisation that goes from incrementation (by 1) to addition to multiplication to exponentiation.

Tetration, denoted by ##{}^nx## or ##x\uparrow\uparrow n## is a number raised to itself as power n times. The one you have written is denoted in Tetration notation by ##{}^2x## or ##x\uparrow\uparrow 2## (the latter is Donald Knuth's notation, which was designed to be amenable for easy further generalisation). Note that the calculation needs to be done in the order from top right towards bottom left, otherwise you just end up with ##x^{(n-1)x}##.

You can read more about Tetration here.

As you would expect, the process of generalisation and extension can be continued indefinitely many times to get even bigger operations called hyperoperations. This leads to the fascinating (but not terribly useful) study of Very Large Numbers like Graham's Number and beyond.
 
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Thank you for your help!
 
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