What is the optimal design for a buoy tether in a large river?

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The discussion centers on the design and calculations for a buoy tethered in a large river, specifically focusing on a vertical cylindrical buoy made of glass-fiber-reinforced plastic. Key points include the buoy's dimensions, the length of the tethering cable, and the conditions under which the cable should snap if water depth exceeds 90 feet. Participants highlight the need for additional information, such as river current, to accurately compute the forces acting on the cable at various depths. The conversation also references a similar homework question from the past, emphasizing the importance of considering environmental factors. Overall, the thread illustrates the complexities involved in buoy design and the necessity for comprehensive data to solve the problem effectively.
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Consider a buoy in the form of a vertical right circular cylinder of outside diameter (D) of 8 feet, and
height (H) of 12 feet. The buoy is a hollow cylinder formed of glass-fiber-reinforced plastic (FRP)
that is ½-inch thick. The buoy is to be placed in a large river and tethered to the bottom by a cable
that is 80 feet long. The cable is supposed to snap if the water depth exceeds 90 feet. Compute the force on the cable at different river depths and the force at which
the cable should be designed to snap. Create a graph of cable force as a function of river depth. I'm totally lost. No idea where to begin.
 
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Binkai said:
Consider a buoy in the form of a vertical right circular cylinder of outside diameter (D) of 8 feet, and
height (H) of 12 feet. The buoy is a hollow cylinder formed of glass-fiber-reinforced plastic (FRP)
that is ½-inch thick. The buoy is to be placed in a large river and tethered to the bottom by a cable
that is 80 feet long. The cable is supposed to snap if the water depth exceeds 90 feet. Compute the force on the cable at different river depths and the force at which
the cable should be designed to snap. Create a graph of cable force as a function of river depth. I'm totally lost. No idea where to begin.

Hi welcome to physicsforums. :smile:
However, isn't that a homework question? Please look under Thread / Thread Starter of:
https://www.physicsforums.com/forumdisplay.php?f=61

Homework questions go here:
https://www.physicsforums.com/forumdisplay.php?f=152
 
I remember getting this same question in 9th grade in 1971, but it was a steel buoy. I answered it "not enough information." I went on to explain that I needed the river current. This would obviously be at flood stage, where the component of line tension caused by the current may dominate over buoyant forces. The teacher gave me full credit.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

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