What Is the Optimal Inner Radius to Minimize Electric Field in a Coaxial Cable?

AI Thread Summary
The discussion focuses on determining the optimal inner radius 'a' in a coaxial cable to minimize the maximum electric field for a given potential difference 'V0' and fixed outer radius 'b'. The potential is expressed using Laplace's equation, leading to the equation V(r) = (V0 ln(r/b))/(ln(a/b)). The electric field is derived as the negative gradient of the potential, E = -∇V. The goal is to find the inner radius 'a' that results in the largest value of the electric field being minimized, which involves evaluating the electric field at various points on the conductors. The analysis aims to identify the point where the maximum of the minimum electric fields occurs.
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Homework Statement


If anyone could clarify this statement for me, I'm having a bit of difficulty interpreting what the heck I'm supposed to do:

"For a given potential difference V0 between the inner and outer conductors and for a given fixed value of b, determine the inner radius a for which the largest value of the electric field is a minimum."I found the potential fairly easily using Laplace's equation
V(r) = \frac{V_0 ln(r/b)}{ln(a/b)} (a is inner radius, b is outer)
I know that the electric field is the negative gradient of potential, but I really don't know what they are getting at.
 
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Homework EquationsV(r) = \frac{V_0 ln(r/b)}{ln(a/b)}E=-\nabla VThe Attempt at a SolutionI think what they are looking for is the minimum value of the largest electric field (so the maximum of the minimums). You can use the equation for the electric field to determine the electric field at various points on the surface of the inner and outer conductors. Then, you can compare the values at these points to find the point with the maximum of the minimums. This will give you the inner radius a that produces the largest value of the electric field that is also a minimum.
 
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