What is the Origin of the Approximation?

AI Thread Summary
The discussion focuses on understanding an approximation in a textbook derivation related to the expression 1/(a)(1 - x/a)^(-1). The approximation simplifies to 1/(a)(1 + x/a) by using the geometric series expansion for 1/(1 - y), where y is substituted with x/a. Participants clarify that the series in question is indeed a geometric series, which converges under the condition that y < 1. The conversation highlights the importance of recognizing series expansions in mathematical derivations. Overall, the approximation is derived from the geometric series concept.
Beer-monster
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Hi

Homework Statement



I'm trying to follow and work through a derivation in my textbook, making sure I can replicate the steps myself and understand what's happening. However, I came across this approximation and can't seem to figure out where it comes from or why and the book gives no clues.


Homework Equations



The general form is:

\frac{1}{a}\left(1-\frac{x}{a}\right)^{-1} \cong \frac{1}{a}\left(1+\frac{x}{a}\right)


Could anyone please explain this to me?
 
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1/(1-y)=1+y+y^2+y^3+... The series converges if y<1. Put y=(x/a) and approximate by only keeping the first two terms.
 
Thanks a lot.

Could you tell me which series that is?
 
Beer-monster said:
Thanks a lot.

Could you tell me which series that is?

Geometric. The easiest of all.
 
I see it now.:blushing:

Been a while since I last saw one of those.
 
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