What is the oxidation state of oxygen in the products of this reaction?

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In the reaction 2C2H2 + 5O2 -> 4CO2 + 2H2O, the oxidation state of oxygen in the reactants is 0, while in the products, it is -2. The carbon in acetylene (C2H2) is oxidized from an oxidation state of -1 to +4 in carbon dioxide (CO2). The confusion arises regarding the reduction products, as oxygen is incorporated into the products CO2 and H2O. Overall, the reaction involves the oxidation of carbon and the reduction of oxygen, with oxygen's oxidation state changing from 0 to -2. Understanding these changes is crucial for grasping the redox nature of the reaction.
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2C2H2 + 5O2 -> 4CO2 + 2H2O


Oxidation: 2C2- -> 4C4+ + 12e-

I am confused to where the reduction products are becuse the oxygens are part of the carbon dioxide and the water. Could somone please help me?
 
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