What is the path on the pV diagram for an isobaric expansion from 2 m^3 to 5 m^3?

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An isobaric expansion from 2 m³ to 5 m³ on a pV diagram is represented by a horizontal line, indicating constant pressure throughout the process. The pressure remains unchanged while the volume increases, resulting in a path parallel to the volume axis. Relevant equations for this scenario include work done (W = PΔV) and changes in internal energy (ΔU = Q - W). Understanding these principles helps clarify the relationship between pressure, volume, and work in thermodynamic processes. The discussion emphasizes the correct graphical representation of isobaric expansion.
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Draw the path in the pV diagram for an isobaric expansion from a volume of 2 m^3 to 5 m^3.



Idk which of these equations are needed because they all are given with this section...
ΔU=Q-W
ΔU=Q+W
W=PΔV
ΔU=Q
W=nRTln(Vf/Vi)
Q-W
ΔU=-W
ΔU=+W
e=W/Qh=1-Qc/Qh
e=1-Tc/Th
ΔS=Q/T




My attempt...

Graph with x being Volume and y being Pressure, a horizontal line from 2-5
 
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An isobaric expansion means that the pressure is kept constant during the expansion. This means that when you graph the expansion on the pV diagram, you will have a line parallel to the V axis.
So what you did was right...
 

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