What is the Peak Current When Discharging Static Electricity?

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Discussion Overview

The discussion revolves around calculating the peak current when discharging static electricity, specifically in the context of a person discharging a capacitance modeled as 100 pF charged to 20,000 V through a resistance of 100 Ω. The focus includes theoretical calculations and the implications of the discharge process.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents a scenario involving a capacitance of 100 pF charged to 20,000 V and a resistance of 100 Ω, seeking to determine the peak current during discharge.
  • Another participant questions the initial voltage and resistance encountered during the discharge process, implying a need for clarity on the discharge path.
  • A subsequent post suggests a peak current value of 200 A, although it is unclear if this is accepted or debated.
  • There is a clarification regarding the notation of amperes, with a participant emphasizing the importance of using the correct capitalization for units.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the peak current value, as the suggestion of 200 A is presented but not confirmed as correct. The discussion remains open with multiple viewpoints on the calculations involved.

Contextual Notes

The discussion does not resolve the assumptions regarding the discharge path or the initial conditions affecting the peak current calculation. The mathematical steps leading to the proposed current value are not fully explored.

Ryantruran
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Homework Statement



When a person shuffles across a dry carpet, their body can be modeled as a charge 100-pF capacitance with one end grounded. Then, if the person touches a grounded metallic object such as a water faucet, the capacitance is discharged and the person experiences a brief shock. Typically, the capacitance may be charged to 20,000 V and the resistance (mainly of one's finger) is 100Ω. Determine the peak current during the discharge and the time constant of the shock.

So,
C=100 pF
V=20,000 V
R= 100 Ω

Homework Equations



T=RC

The Attempt at a Solution



I already Found T=.01 μS
just stuck at the peak current during discharge
 
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Well, when the "switch closes", so to speak, what initial voltage sees what resistance in its path on its way to ground?
 
gneill said:
well, when the "switch closes", so to speak, what initial voltage sees what resistance in its path on its way to ground?

200 a ?
 
Ryantruran said:
200 a ?

Make that 200 A (capital A for Amperes) and I'll agree :smile:
 
I attempted three times to make it capital. not sure why it won't let me. Thanks for the help
 

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