What is the perimeter of a rectangle with a 3:2 ratio and an area of 294 dm2?

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To find the perimeter of a rectangle with a 3:2 ratio and an area of 294 dm², first express the length (L) as 3x and the width (W) as 2x. The area equation becomes 3x * 2x = 294, leading to 6x² = 294. Solving for x gives x = 7, resulting in L = 21 dm and W = 14 dm. The perimeter is then calculated using the formula 2L + 2W, yielding a total perimeter of 70 dm.
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Homework Statement
A rectangle has a ratio of 3:2. The area is 294 dm2. What is the perimeter?
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Hi. Could someone please help me with this? :

A rectangle has a ratio of 3:2. The area is 294 dm2. What is the perimeter?
 
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How am I supposed to calculate this?
 
EMEE_ said:
How am I supposed to calculate this?
What is a rectangle? How do you calculate the area and the perimeter of a rectangle?
 
243519
So the area and ratio are given ( 3:2) and 3 represents the long side and 2 the shorter side. I calculate the area like this: A = L * W ( L is the length and W is the width). I think that the perimeter is 2*W+2*L
 
EMEE_ said:
View attachment 243519 So the area and ratio are given ( 3:2) and 3 represents the long side and 2 the shorter side. I calculate the area like this: A = L * W ( L is the length and W is the width). I think that the perimeter is 2*W+2*L
But you know that the ratio of the length to the width is 3/2, or ##\frac L W = \frac 3 2##. From this equation you can write the length in terms of the width.

Write your area equation using the value given, and write the equation for the perimeter. Keep in mind what I wrote above.
 
Let L=3x and W=2x, where x is unknown.
 
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