What is the Potential Energy of a Spring Between Two Masses?

AI Thread Summary
The potential energy of a spring between two masses can be expressed as PE = (1/2)*k*(d - p)^2, where d is the distance between the masses and p is the relaxed length of the spring. Initial calculations suggested separate horizontal and vertical potential energies, but the overall formula simplifies to the distance-based expression. The discussion emphasizes focusing on the distance between the masses rather than individual coordinates. This approach streamlines the understanding of the spring's potential energy in relation to its relaxed state.
rakshit1992
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A planar object comprises of two masses joined by a linear spring with relaxed length p. The horizontal and the vertical displacements of the two masses are measured relative to a fixed point of reference as shown in the figure. What would be the potential energy of the spring?

My initial guess for this problem are that the spring will have a horizontal PE=(1/2)*k*(z-x)^2 and a vertical PE=(1/2)*k*(w-y)^2.

But something tells me that there might be the possibility of the PE=(1/2)*k*(sqrt(z^2+w^2)-p)^2-(1/2)*k*(sqrt(x^2+y^2)-p)^2.

Please help
 

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Forget the x and y coordinates for the moment. If the distance between the masses is d, how would you express the PE in terms of d and the relaxed length p?
 
In that case, I would assume it to be (1/2)*K*(d-p)^2
 
rakshit1992 said:
In that case, I would assume it to be (1/2)*K*(d-p)^2
OK. Express this in terms of the given quantities.
 
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