What Is the Probability Density of a Non-Wave Electron in a Box?

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I've been wondering, if an electron in a box (of length L) is NOT a wave, what is the probability density in this non-quantum mechanical case?
 
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Non Quantum Mechanical case - don't get it.

But its not a wave in any usual physical sense. To see it the wave propagates in an abstract infinite dimensional Hilbert space.

The wave particle duality is a crock of the proverbial that was outdated when Dirac came up with his transformation theory in about 1927.

It persists today purely because of the semi-historical approach most textbooks take.

To see the real basis of QM check out:
http://www.scottaaronson.com/democritus/lec9.html

For a correct treatment of QM have a look at the first 3 chapters of Ballentine - it may be a revelation - it was for me:
https://www.amazon.com/dp/9810241054/?tag=pfamazon01-20

Thanks
Bill
 
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terp.asessed said:
I've been wondering, if an electron in a box (of length L) is NOT a wave, what is the probability density in this non-quantum mechanical case?

The electron is never a wave, no more so in quantum mechanics than in classical mechanics. Bhobba's observation about a "crock of the proverbial..." is indelicate but accurate.

But you're asking about the probability density for the position of the electron when quantum effects are insignificant. That will be ## \rho(x)=\delta(x-X)## where ##X## is the classical position and ##\delta## is the Dirac delta function. This solution is not physically realizable, although it is easy to construct situations (for example, all of classical mechanics) where it's a useful idealization.
 
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Thank you! I think I get it.
 
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