Screwdriver
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Not a homework question per se, but I'm having some issues with moments of inertia. Say I wanted to calculate the I for a ring. What I would do is:
I = \int r^2dm
m = \lambda L
dm = \lambda dL
I_{ring} = \int_{0}^{L}\lambda r^2dL
And that would give the requiside mr2. My question is, why can't I just integrate THAT up to get the I of a disk. I mean something like this:
I_{disk} = \int_{0}^{A}\int_{0}^{L}\lambda r^2dLdA
Where A is the area of the disk. Doesn't figuring out the I for a ring essentially skip the first step for determining the I for a disk?
I = \int r^2dm
m = \lambda L
dm = \lambda dL
I_{ring} = \int_{0}^{L}\lambda r^2dL
And that would give the requiside mr2. My question is, why can't I just integrate THAT up to get the I of a disk. I mean something like this:
I_{disk} = \int_{0}^{A}\int_{0}^{L}\lambda r^2dLdA
Where A is the area of the disk. Doesn't figuring out the I for a ring essentially skip the first step for determining the I for a disk?