What is the reason for the e field being 0 inside of a hollow conductor?

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The discussion centers on the electric field (E) inside a hollow conductor, specifically addressing a scenario with an inner conductor having a linear charge density and an outer hollow conductor with no net charge. It is clarified that the electric field is zero for distances less than the radius of the inner conductor (1.5 cm) due to the properties of conductors, where charges reside on the surface. The confusion arises from the assumption that E should also be zero in a hollow conductor, but it is emphasized that E is zero inside the conductor because any internal electric field would cause free charges to redistribute until equilibrium is reached. The use of Gauss's law is recommended to analyze the electric field in such configurations. Ultimately, the key takeaway is that within a conductor, the electric field is zero as charges move to neutralize any internal fields.
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Homework Statement


An inner conductor has radius 1.5cm and linear charge density 6 nC/m and the outer conduct has no net charge. The outer conductor has radius 4.5cm and 6.5cm.
Find the e field for all values of R where R is the perpendicular distance from the common axis of cylindrical system.In the book they had that E=0 for r<1.5cm.
Why is that, shouldn't E=0 if it was a hollow conductor. In this case the book is drawing the conductor has a solid cylinder, not a hollow one. The big conductor is hollow with the 2 radius but not he smaller one. Can someone explain this to me.

Edit-I think they assumed the charge would be 0 for r<1.5cm
 
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Hmm I think I would need to see a pic to make sure I fully understand what the object is. You should be able to use Gauss for each situation in these types of problems.
 
If there is a non-zero field within a conducting material, what will happen to the charges which are free to move?
 
ask urself what will happen if there is an electric field set up within a conductor. what will happen to the charges?
 
In a conductor the charge is on the surface. Hence E will be zero
 
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