What is the reflection coefficient on a transmission line at a resistor halfway?

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SUMMARY

The reflection coefficient on a coaxial transmission line with resistors is calculated using the formula \(\Gamma_{L} = \frac{Z_L-Z_o}{Z_L+Z_o}\). To determine \(Z_L\) at the halfway point, the equivalent impedance of resistor \(b\) must be calculated using only the length \(L/2\) of the transmission line. This involves transforming the circuit to find the impedance seen by resistor \(a\) and then applying the reflection coefficient formula. The correct approach is to treat the resistors in parallel to find a single impedance at the halfway mark.

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Homework Statement


If I have a coaxial transmission line, with a resistor halfway through, and another resistor at the end, how do I calculate the reflection coefficient for the spot where the resistor is halfway?

Here is a diagram of what I mean. Dashes and dots are are the lines, and } are resistors.

----------
...}a...}b



Homework Equations


\Gamma_{L} = \frac{Z_L-Z_o}{Z_L+Z_o}


The Attempt at a Solution


I am pretty sure the formula I am supposed to use is \Gamma_L = \frac{Z_L-Z_o}{Z_L+Z_o}. What I am not sure is what value to choose for Z_L. Do I take Z_o in parallel with R_A?
 
Last edited:
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you know how you can take any length of transmission line plus an impedance at the end, and transform it into a single impedance that the source sees?

Well, put your finger over resistor a and the rest of the circuit, and apply that formula to transform your circuit from
L/2 of wire-> impedance a -> L/2 of wire -> impedance b
into
L/2 of wire -> impedance a -> equivalent impedance B

you need to use the length L/2, not L, when you calculate the equivalent impedance for resistor b, because you're calculating the equivalent impedance that resistor a sees. Next, now that resistor behaves just like they do in your circuits class. Take equiv b in parallel with a (assuming a branches across and connects the wires) to find a single impedance at the "end of the wire" (which represents what impedance is seen at the halfway point). Then apply your reflection equation.
 

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