What is the relationship between force, acceleration, and mass in a lift?

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The discussion centers on understanding the relationship between force, acceleration, and mass in the context of a body suspended in a lift. The correct method to find the mass involves recognizing that the net force acting on the body is the difference between the tension in the spring balance and the weight of the body. The tension reading of 70N indicates the force acting upward, while the gravitational force is calculated using the mass and gravitational acceleration. Applying Newton's second law, the net force can be expressed as F = ma, leading to the conclusion that the mass is 5kg when the upward acceleration is considered. The conversation highlights the importance of identifying the unbalanced forces to correctly apply the principles of physics.
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Homework Statement
A body hangs from a spring-balance which is suspended from the ceiling if a lift. What is the mass of the body if the balance registers a reading of 70N when the lift has an upward acceleration of 4.0ms^-2. (g = 10ms^-2)
Relevant Equations
F = ma
Weight = mg
Much like the previous question I've posted I was quite unsure of the the method I should take and resorted after many attempts to just trial and error which resulted in getting the correct answer of 5kg after dividing the weight of 70N by 14ms^-2 (sum of upward acceleration and gravitational field strength). Can someone please explain why this works, or the proper method to the question?
 
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TH02 said:
Homework Statement:: A body hangs from a spring-balance which is suspended from the ceiling if a lift. What is the mass of the body if the balance registers a reading of 70N when the lift has an upward acceleration of 4.0ms^-2. (g = 10ms^-2)
Relevant Equations:: F = ma
Weight = mg

Much like the previous question I've posted I was quite unsure of the the method I should take and resorted after many attempts to just trial and error which resulted in getting the correct answer of 5kg after dividing the weight of 70N by 14ms^-2 (sum of upward acceleration and gravitational field strength). Can someone please explain why this works, or the proper method to the question?
Why do you think it doesn't work?

What is the ##F## in ##F = ma##? And don't just say "force"!
 
Would it be the tension in the spring? Or the weight of the body?
 
Let’s see your fbd.
 
Chestermiller said:
Let’s see your fbd.
IMG_20200703_162730234.jpg


I am not sure if I've added all the forces I need
 
TH02 said:
View attachment 265762

I am not sure if I've added all the forces I need
Gravity? Isn't ##T = 70N##?
 
PeroK said:
Gravity? Isn't ##T = 70N##?
I'm sorry, I'm getting quite confused
 
TH02 said:
I'm sorry, I'm getting quite confused
The question tells you that the spring balance reads ##70N##. That means that ##T = 70N## in your diagram.
 
  • #10
PeroK said:
The question tells you that the spring balance reads ##70N##. That means that ##T = 70N## in your diagram.
IMG_20200703_164919018.jpg

Is this more accurate?
 
  • #11
That looks better. What does ##a = 4m/s^2## tell you?
 
  • #12
PeroK said:
That looks better. What does ##a = 4m/s^2## tell you?
That I have a vertical acceleration of 4m/s^2?
 
  • #13
TH02 said:
That I have a vertical acceleration of 4m/s^2?
Yes, okay, but more than that. Hint: Newton's 2nd Law.
 
  • #14
PeroK said:
Yes, okay, but more than that. Hint: Newton's 2nd Law.
I'm not following, is it that the force being applied to the body is directly proportional to the acceleration acting on the body?
 
  • #15
TH02 said:
I'm not following, is it that the force being applied to the body is directly proportional to the acceleration acting on the body?

The ##F## in Newton's law is the unbalanced force, which is the vector sum of all forces on the body. In this case we have:
$$F = T - mg, \ \ \text{and} \ \ F = ma$$
Where, to be precise, I have taken upwards as the positive dircetion.
 
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  • #16
PeroK said:
The F in Newton's law is the unbalanced force, which is the vector sum of all forces on the body. In this case we have:
F=T−mg, and F=ma
Where, to be precise, I have taken upwards as the positive dircetion.
Ahhh I see
IMG_20200703_171831782.jpg

Sorry for taking so long to get there! I appreciate the help
 
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  • #17
TH02 said:
I'm not following, is it that the force being applied to the body is directly proportional to the acceleration acting on the body?
 
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