What is the relationship between force and surface area when pushing a crate?

  • Thread starter Thread starter Kdawg
  • Start date Start date
  • Tags Tags
    Area
AI Thread Summary
When pushing a crate across the floor, the force required to maintain constant speed is influenced by the friction force, which is calculated using the equation F_friction = μ_k F_normal. Reducing the surface area in contact with the floor does not affect the friction force, as it is proportional to the weight of the object rather than the contact area. Therefore, even with half the surface area, the force needed to push the crate remains the same as before. This highlights that friction is dependent on the normal force and the coefficient of friction, not the area of contact. Understanding this relationship is crucial for accurately predicting the force needed to move objects.
Kdawg
Messages
34
Reaction score
0
You are pushing a wooden crate across the floor at constant speed.You decide to turn the crate on end, reducing by half the surface area in contact with the floor. In the new orientation, to push the same crate across the same floor with the same speed, the force that you apply must be what compared to the original force?
 
Physics news on Phys.org
This can't be that hard
 
Depending on your level, force of friction is using a simple model calculated by the following:
<br /> F_\textrm{friction} = \mu_k F_\textrm{normal}<br />
Keep in mind this isn't a fundamental law, it's an experimental relation between the magnitude of the friction force and the magnitude of the normal force.
 
Remember that the friction force is proportional to the weight of the object, not the area of contact!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top