What is the Relationship Between Tension and Velocity in a Vibrating String?

AI Thread Summary
The relationship between tension and velocity in a vibrating string is defined by the equation v = √(T/μ), where T is tension and μ is linear mass density. A participant expresses concern about insufficient information to solve a specific problem, particularly noting the absence of the string's mass. They agree that the problem lacks enough data for a complete solution. The discussion concludes with a positive remark about the quality of instruction received. Understanding the variables involved is crucial for solving related physics problems.
Sho Kano
Messages
372
Reaction score
3

Homework Statement



(Problem #1 on this page.)[/B]
Untitled.png


Homework Equations


##v=\sqrt { \frac { T }{ \mu } } =\lambda f##

The Attempt at a Solution


I don't think there is enough information,
##v=\sqrt { \frac { Mg }{ m/L } } ##
m, the mass of the string is not given
 
Physics news on Phys.org
I agree that there is not enough information given.
 
  • Like
Likes Sho Kano
OK this is solved then. I have a great teacher.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top