What is the Required Pressure Difference to Heat 2 Moles of Gas?

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SUMMARY

The required pressure difference to heat 2 moles of gas from 12 K to 276 K in a volume of 0.001 m³ can be calculated using the ideal gas law, PV=nRT. The calculations involve substituting the values for pressure (P), volume (V), number of moles (n), the gas constant (R), and temperature (T) into the equation. The correct approach is to calculate the pressure at both temperatures and then find the difference, ensuring that Avogadro's number is not used incorrectly in the calculations.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Basic knowledge of thermodynamics and gas behavior
  • Familiarity with units of pressure, volume, and temperature
  • Ability to perform algebraic manipulations and calculations
NEXT STEPS
  • Study the Ideal Gas Law in detail, focusing on its applications
  • Learn how to calculate pressure changes in thermodynamic processes
  • Explore the implications of temperature changes on gas behavior
  • Review common mistakes in gas law calculations, particularly regarding units
USEFUL FOR

Students studying thermodynamics, physics enthusiasts, and anyone involved in chemistry or engineering who needs to understand gas behavior under varying temperature and pressure conditions.

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Homework Statement


What must the pressure difference be to raise 2 moles of gas at .001 m³ from 12 K to 276 K?


Homework Equations


PV=nRT



The Attempt at a Solution


PV=nRT
P(.001 m³)=(2/6.02x10²³)(8.31)(12)

P(.001 m³)=(2/6.02x10²³)(8.31)(276)

Subtract the two answers to get the difference...
 
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What is your question?
 
Why are you dividing by Avogadro's number? 'n' in your equations is the number of moles. Just sub in your values, make sure you divide by the volume to find P before you subtract the two pressures.
 

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