What is the resistance of a wire if its diameter is doubled?

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Discussion Overview

The discussion revolves around the resistance of a wire when its diameter is doubled, particularly in the context of a Cambridge IGCSE exam question. Participants explore the implications of changing the diameter on resistance, considering both direct current (DC) and alternating current (AC) scenarios, as well as the relationship between volume, length, and cross-sectional area.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant questions the exam's answer indicating a 16-fold decrease in resistance, expressing confusion over how this conclusion was reached.
  • Another participant suggests that if DC resistance is proportional to cross-sectional area, then a decrease by a factor of 1/4 could be reasonable.
  • Discussion includes the skin effect in AC, which may influence resistance differently than in DC.
  • Participants inquire about the implications of length when diameter is doubled, noting that the question does not specify changes in length.
  • One participant asserts that if the volume remains constant while the diameter doubles, the length must decrease, which would affect resistance calculations.
  • A mathematical expression for the volume of a cylinder is provided, prompting further exploration of how changes in diameter and volume relate to length and resistance.

Areas of Agreement / Disagreement

Participants express differing views on how resistance changes with diameter, with some supporting the exam's answer and others proposing alternative interpretations. The discussion remains unresolved regarding the exact relationship between diameter, length, and resistance.

Contextual Notes

Participants highlight the importance of assumptions regarding volume and length in resistance calculations, indicating that the problem's conditions are critical to understanding the changes in resistance.

Kevin J
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This was a MCQ question on one of my Cambridge IGCSE Exams, the answer key said that the resistance would decrease by 16 folds (1/16 less then the previous one), I don't know how they got 16 from? (Apparently, I answered 1/4 and it was wrong)
 
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Your question doesn't sound like homework. But why did you say 4? Are you thinking DC or AC?
 
If DC resistance is directly proportional to crossectional area, then 1/4 sounds right.
πR∧2 VERS. π(2R)∧2 (Assuming the length is constant.)
 
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Here's the question, the mark scheme says it's D, how do you get D?
20181109_215224.jpeg
 

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What happens to the length?
 
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Chestermiller said:
What happens to the length?
It doesn't say anything, it was a question from CAMBRIDGE IGCSE
 
It says the new cylinder is the same volume as the old one.
 
ChemAir said:
It says the new cylinder is the same volume as the old one.
I have a feeling that the length decreases right?
 
  • #10
The volume of a cylinder is $$V=\pi\frac{D^2}{4}L$$If D doubles and V remains constant what does L have to do?
 
  • #11
Kevin J said:
Here's the question, the mark scheme says it's D, how do you get D? View attachment 233716
Kevin J said:
It doesn't say anything, it was a question from CAMBRIDGE IGCSE
Kevin J said:
I have a feeling that the length decreases right?
I does in fact mention the length. It states the volume of the putty remains constant as the diameter is increased by twice. For that to be true, the length must also change. Remember that resistance is approximated from resistivity and is inversely proportional to the cross-sectional area of the putty while also being proportional to the putty's length. If the length of the putty decreases while the area increases, the resistance will decrease by the seemingly "too large" factor shown above. Hope this helps.

The easiest way to handle these problems is to substitute in for some numbers and see what happens when you change the parameters.
 
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