What is the safe speed limit for a car on a curved highway?

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The discussion focuses on calculating the safe speed limit for a car on a curved highway with a radius of 55m and a maximum static friction force of 8740N. The calculations involve using the formula for centripetal force, leading to different interpretations of the resulting speed. One participant initially calculated a speed of 0.144m/s, while others arrived at 24.59m/s and 604.65m/s. The confusion stems from the application of the equations and the values used in the calculations. Ultimately, the correct speed limit for safe negotiation of the curve is determined to be approximately 24.59m/s.
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Homework Statement


On a highway curve with radius 55m, the maximum force of static friction that can act on a 795kg car going around the curve is 8740N. What speed limit should be posted for the curve so that cars can negotiate is safely?


Homework Equations


ƩF=ma, a=v^2/r


The Attempt at a Solution



8740N=795kg(v^2/55m)

8740N= 4375m*kg(v^2)

0.200m/s= v^2

v=0.144m/s

it looks like I performed my math correctly, but I need a second opinion. The solution that I solved does not appear in the answer choices of my practice exam.
 
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the answer choices are
A) 241.23m/s
B)10.99m/s
C)7798.95m/s
D)604.65m/s
E)24.59m/s
 
It is D)

m v2 / r = F

v = √(98740.55/795) = 604.65408805031446540880503144654 :wink:
 
thanks, but where did I go wrong with my math? everytime I isolate v I get letter E
 
Mentz114 said:
It is D)

m v2 / r = F

v = √(98740.55/795) = 604.65408805031446540880503144654 :wink:

Thanks, but I believe the velocity that you gave did not work, :( 11.14 would be the velocity.

Here's what I did, 8740N*55/795 = v^2

v = 24.59m/s
 
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