What is the significance of pH in a basic solution?

  • Thread starter Thread starter Bipolarity
  • Start date Start date
  • Tags Tags
    Ph Significance
AI Thread Summary
pH is defined as -log[H+] and applies to both acidic and basic solutions, as water always dissociates into H+ and OH- ions, maintaining a balance. In a basic solution, such as ammonia, while hydroxide ions are produced, there are still H+ ions present from water's autodissociation. The relationship pH + pOH = 14 holds true because it reflects the equilibrium between H+ and OH- concentrations in any aqueous solution, not just pure water. Adding an acid increases H+ concentration, which shifts the equilibrium and affects the pOH, but OH- ions remain in the solution. Understanding this equilibrium is crucial for grasping the significance of pH and pOH in different solutions.
Bipolarity
Messages
773
Reaction score
2
I am a little confused about the meaning of pH, especially when you have a basic solution. I know that pH = -log[H^{+}], but I don't understand how you can have a pH for a basic solution. Don't basic solutions only produce hydroxide ions?

I know that pH + pOH = 14 but why this equation be true for anything other than water?

For example, consider the basic solution of ammonia to produce ammonium ions and hydroxide ions.

NH_{3}(g) + H_{2}O(l) \rightleftharpoons NH^{+}_{4}(aq) + OH^{-}(aq)

Knowing the concentrations and the base-dissociation constant, we could easily calculate [OH^{-}] and from that we can get pOH, but what is the significance of pH if there is no H^{+} ions?
 
Chemistry news on Phys.org
Why do you say other than water? Water has its own dissociation constant Kw=10-14=[H3O+][OH-]. Taking logarithm on both sides, I think you would get the same result.

And it is due to the fact that at temperature of your room, water dissociate in the aforesaid proportions; therefore, under aquatic, room temperature, it is always true. If any of the ions are in excess, the equilibrium of the dissociation reaction would shift, so that some of those would recombine and be back to equilibrium. Of course you can analyse the free energy and understand more precisely, but that's not quite relevant.
 
Thank you for your replies everyone. I do know that water dissociates, but I still don't understand the significance of pOH in an acidic solution and the significance of pH in basic solution.

Acid produces hydrogen ions in water, but the hydroxide ions come from the water and not from the acid? What is the point in counting the water's hydroxide ions toward the calculation of pOH for the acid? I'm not sure I get it... all I know is that water dissociates into both hydrogen and hydroxide ions. But acid dissociates ONLY into hydrogen right? So where does the pOH for the acid come from? And pH for the base? Am I missing something?

Thanks!

BiP
 
Have you heard about equilibrium?

Water dissociates producing both H+ and OH-. When you add an acid you increase the concentration of H+, shifting water dissociation equilibrium to the left - but there will be still OH- in the solution.
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
Back
Top