What is the solution for an inverse third order equation when solving for X?

  • Thread starter Thread starter cooka111
  • Start date Start date
  • Tags Tags
    Inverse
AI Thread Summary
To solve the inverse third order equation for X, start by multiplying the equation y = y_{0} + (a/x) + (b/x^2) + (c/x^3) by x^3 to eliminate the denominators. This transforms the equation into a cubic polynomial of degree three. The roots of this polynomial can be found using Cardano's method, which is a standard approach for solving cubic equations. The discussion highlights the importance of maintaining the integrity of the data when swapping axes, as it can significantly affect the R² value. Understanding these steps is crucial for independently calculating both Y and X values.
cooka111
Messages
1
Reaction score
0
I have a question about solving a formula.

I have a set of data which I have fit to an inverse third order equation, if I swap the axes (use X as Y and vise versa), R2 suffers dramatically but I would like to calculate both Y and X values independantly. I am wondering what the solution for the following equation is when cast to calculate X. My algebra is a little rusty and I am not sure where to start.

y = y_{0}+\frac{a}{x}+\frac{b}{x^{2}}+\frac{c}{x^{3}}

Assuming I have values for a,b,c, and yo, how do I solve this for x?
 
Mathematics news on Phys.org
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Thread 'Imaginary Pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Back
Top