What Is the Speed of the Ball When Kicked Back in This Soccer Scenario?

  • Thread starter Thread starter OUstudent
  • Start date Start date
  • Tags Tags
    Speed Velocity
AI Thread Summary
In the soccer scenario, Jack kicks the ball to John at a velocity of 5.40 m/s, and they are 6 meters apart. The time taken for the ball to reach John is calculated to be 1.11 seconds. After John kicks the ball back, the total time for the entire exchange is 2.6 seconds. The user struggles with the calculations to determine the speed of the ball when kicked back to Jack, indicating confusion in the process. The discussion highlights the need for clarity in solving kinematic equations related to the motion of the ball.
OUstudent
Messages
14
Reaction score
0

Homework Statement


Jack and John are standing 6m apart from each other playing soccer. Jack kicks the ball to John and John kicks it back immediately. Jack kicked the ball with a velocity of 5.40 m/s and after 2.6 s he got the ball back. Suppose there's no deceleration of the ball when it's moving and that we can neglect the time for John to kick the ball. What is the speed of the ball when it's kicked back to Jack?


Homework Equations



V= D/T

The Attempt at a Solution


5.4 m/s = 6 /t = 1.11 seconds
1.11 + 2.6 = 3.71 seconds total
3.71 = ( (6/5.4) + (6/v) ) = 2.3

I'm doing something wrong, because I'm not getting the right answer.
thanks in advance
 
Physics news on Phys.org
OUstudent said:
5.4 m/s = 6 /t = 1.11 seconds
1.11 + 2.6 = 3.71 seconds total
1.11 is the time it takes for the ball to reach John. 2.6 is the total time.
 
I'm an idiot...

Thanks
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Relative velocity passing a ball between two soccer players
Replies
5
Views
2K
What's the speed of the ball 1 second after it was kicked?
Replies
7
Views
3K
Projectile Motion Problem: Kicking a soccer ball over a fence
Replies
11
Views
2K
Oblique soccer shot calculation task
Replies
38
Views
3K
Finding the Speed of a head hit by a soccer ball
Replies
2
Views
4K
Projectile Question -- Kicking a soccer ball through two holes in two walls....
Replies
2
Views
2K
What's the minimum initial speed to score
Replies
6
Views
2K
What is the Maximum Height Achieved by a Soccer Ball Kicked at a 45° Angle?
Replies
11
Views
2K
Calculating momentum of soccer ball.
Replies
6
Views
6K
Solving a Ball Thrown off a Cliff: How Long Does it Take?
Replies
4
Views
2K

Hot Threads

Recent Insights

Back
Top