What is the Sum of a Geometric Series with a Given Initial Value and Ratio?

mtayab1994
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Homework Statement


I already counted V_{0}=-1

and q=\frac{1}{3}

given: V_{n}=1-\frac{2}{U_{n}}





Homework Equations



count: \sum_{k=0}^{n}V_{k}


The Attempt at a Solution




i counted the sum and i got : ((\frac{1}{3})^{n+1}-1)(\frac{2}{3})

is that correct?
 
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What is Un ... don't make us make assumptions.
 
I got it anyway. It's


S=-\frac{3}{2}(1-(\frac{1}{3})^{n+1})
 
Well done.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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