What is the tension at point A below the x-z plane?

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Homework Help Overview

The problem involves determining the tension at point A, which is located below the x-z plane. The challenge arises from the lack of information regarding the exact distance of point A below the plane, which is crucial for solving the problem.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need for additional information regarding the distance below the x-z plane to calculate tension. There are suggestions to use geometric relationships, such as 3-D Pythagoras, to find this distance based on given dimensions.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and questioning the assumptions about the distance below the x-z plane. Some guidance has been offered regarding the use of geometric methods to approach the problem.

Contextual Notes

There is a mention of specific dimensions (c and 8 in.) and the distance between two masses (18 in.) that may be relevant to the calculations, but the exact relationship to the problem remains unclear.

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So I am thinking about this problem, and what I don't understand is how at that point A, it is below the x-z plane, but it is not given how far below it is. If I knew, I could solve for the tension in the y-direction and set it equal to the weight.

I must be able to use c and 8 in. to get me closer to that distance below the x-z plane, but I'm not sure how
 

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Woopydalan said:

Homework Statement


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The Attempt at a Solution



So I am thinking about this problem, and what I don't understand is how at that point A, it is below the x-z plane, but it is not given how far below it is. If I knew, I could solve for the tension in the y-direction and set it equal to the weight.

I must be able to use c and 8 in. to get me closer to that distance below the x-z plane, but I'm not sure how

use 3-D Pythagoras to calculate how far below the x-z plane the mass is each time. remember, the two masses are 18" apart.

If you don't understand 3-D Pythagoras, use normal Pythagoras on the 8" and c to find the direct distance across that void, the normal Pythagoras with the 18" cable/rod (or what ever it was) to calculate how far below the x-z plane A was in each case.
 
Last edited:
If (xA, yA, zA) and (xB, yB, zB) are the coordinates of A and B, respectively, how can you express the length of the wire in terms of these coordinates?
 
Here is my attempt
 

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Your work looks good, except you seem to have made a mistake in the final evaluation of T in part (a).
 
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