What is the TOPOLOGICAL DIMENSION of?

Take_it_Easy
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Let {\mathbb I} = {\mathbb R} \setminus {\mathbb Q} the set of the irrational numbers of the real line.

What is the topological dimension of
{\mathbb R}^2 \setminus {\mathbb I} \times {\mathbb I} ?
 
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Take_it_Easy said:
Let {\mathbb I} = {\mathbb R} \setminus {\mathbb Q} the set of the irrational numbers of the real line.

What is the topological dimension of
{\mathbb R}^2 \setminus {\mathbb I} \times {\mathbb I} ?


Just discovered, by myself, that it is 1 .

:-p

I just hope that someone can enjoy this result as I do!
 
Last edited:
Could you explain what is topological dimension please?
 
apparently

We say a topological space X has topological dimension m if every covering C of X has a refinementC' in which every point of X occurs in at most m+1 sets in C' , and m is the smallest such integer. Actually, this version of the definition of dimension (called the covering dimension) makes the most sense for compact spaces X.
 

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