- #1
claudiadeluca
- 9
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Hi, I need help with the following exercise:
We have a square circuit, with 4 capacitors, 1 on each side of the square, all with the same capacitance C. Calculate the total capacitance of the system of capacitors between the two diagonally opposite corners of the square, A and B.
This is how I solved it, could you tell me if it's right?
A ) 2 capacitors (from A to B ): they are in series
B ) 2 capacitors (from B to A): they are in series
A )1/Ceq = 1/C1 + 1/C2= 2/C --> A-Ceq=C/2
B )1/Ceq = 1/C3 + 1/C4= 2/C --> B-Ceq=C/2
Now A-Ceq and B-Ceq are in a parallel configuration:
C) Ceq = C/2 + C/2 = C
The total capacitance is equal to C?
Thank you.
Homework Statement
We have a square circuit, with 4 capacitors, 1 on each side of the square, all with the same capacitance C. Calculate the total capacitance of the system of capacitors between the two diagonally opposite corners of the square, A and B.
This is how I solved it, could you tell me if it's right?
A ) 2 capacitors (from A to B ): they are in series
B ) 2 capacitors (from B to A): they are in series
A )1/Ceq = 1/C1 + 1/C2= 2/C --> A-Ceq=C/2
B )1/Ceq = 1/C3 + 1/C4= 2/C --> B-Ceq=C/2
Now A-Ceq and B-Ceq are in a parallel configuration:
C) Ceq = C/2 + C/2 = C
The total capacitance is equal to C?
Thank you.