What is the total time in the air for the parachutist's jump?

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To determine the total time in the air for the parachutist, first calculate the time taken to fall 53.2 meters under gravity, using the formula for free fall. Next, find the time required to decelerate from the speed reached during free fall to the landing speed of 3.23 m/s, applying the deceleration rate of 2.00 m/s². The calculations involve solving for time in both phases of the jump: free fall and deceleration. By accurately applying the physics equations, the total time in the air can be derived. This problem emphasizes the importance of breaking down the motion into distinct phases for accurate analysis.
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Hey could someone explain to me this problem because i tried every single variation of the rules i learned in class, v = delta d/ delta t a= delta v/ delta t ect.. and i kept getting the wrong answer.

A parachustist jumps from an airplane and freely falls y=53.2 m before opening his parachute. Thereafter, he decelerates at a=2.00 m/s2. As he reaches the ground, his speed is 3.23 m/s. How long was the parachutist in the air?
 
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First step - free fall - requires you to find time needed to cover distance while accelerating at g. Second step - slowing down - requires you to find time necessary to slow down from the final speed of free fall (you will have to calculate it from time and g) to the landing speed.
 
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