What is the train's final speed?

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A train initially traveling at 40 km/h accelerates at 5.0 m/s² for 0.80 seconds. The initial speed is converted to meters per second, resulting in 11.1 m/s. Using the equation Vf = Vo + at, the final speed is calculated as 15.1 m/s. The discussion emphasizes the importance of unit conversion and correct application of kinematic equations. The final speed of the train is confirmed to be 15.1 m/s.
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Homework Statement



Hey guys..
A train traveling at 40km/h accelerates at a rate of 5.0m/s^2 for 0.80s.what is its final speed.

2. Homework Equations [/b
i believe this is the equation a=v1-v0/t


The Attempt at a Solution


Im totally stuck i tried but due to a lack of ti 84 i can't get the calculations...Please help
 
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One thing you need to notice is that the initial speed is in km/h and the acceleration is in m/s^2 so I would adjust the initial velocity to be in m/s.
 
40 km/h = 11.1 m/s

Now Use this equation: Vf = Vo + at to solve for Vf.
 
so it would be Vf=0+5.0(.80)
which equals 4 so the answer would be 4km/h? I am sorry you know the units?
 
Vo is 11.1 m/s, not 0. And the units are m/s.
 
thanks allot so here's my answer

v=11.1+5.0(.80)
4+11.1
15.1m/s?
 
As far as I can tell, that looks good.
 
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