What is the truth value of this statement about numbers?

  • Thread starter Thread starter Lococard
  • Start date Start date
  • Tags Tags
    Value
Click For Summary

Homework Help Overview

The problem involves determining the truth value of a mathematical statement concerning non-negative real numbers x and y. The statement suggests a relationship between x squared and y plus one, prompting participants to explore its validity.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the interpretation of the original statement and whether it is asking to show the existence of an x for all y such that x squared is less than y plus one. Some question the clarity of the problem as presented.

Discussion Status

There is an ongoing exploration of the statement's truth value, with some participants suggesting that the statement may be true under certain conditions. Others are seeking clarification on how to approach proving the statement.

Contextual Notes

Participants note that the problem may involve specific constraints related to non-negative real numbers and the implications of the statement's structure. There is mention of a teacher's guidance to attempt disproving the statement rather than proving it true.

Lococard
Messages
25
Reaction score
0

Homework Statement


Determine the truth value of the statement.

There exists x for every (xsquared smaller than y+1)

x and y a set of non-negative real numbers

Sorry i don't know how to do the maths symbols on the computer.


Homework Equations



All the numbers i have used make the statement true. The teacher said to try and proove the statement false, rather than prooving it correct.

Another teacher said it is to do with fractions.


The Attempt at a Solution



As above
 
Physics news on Phys.org
Is that the question as it was given? Is the question;

Show that there exists a value of x such that for every value of y, [itex]x^2 < y+1[/itex] ?

If that is the question, the statement is actually true.
 
Ah ok.


How would i prove this?

I looked at a few of the proven workings but nothing resembles a similar question?
 
To prove it: Since y must be a non-negative real number, the smallest the RHS can be is 1. So every single time it suffices to choose a value of x^2 less than 1, which is a value of x less than 1.
 
In fact any number [itex]x < \sqrt{y + 1}[/itex] would do. If you'd want to be dull you could just take x = 0 for all y.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 25 ·
Replies
25
Views
4K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K