What is the value of this complex line integral?

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Discussion Overview

The discussion revolves around evaluating the complex line integral given by the expression \(\int\limits_{0}^{2\Pi} e^{-\sin t} \sin\lbrace (\cos t ) - (n-1) t \rbrace dt\). Participants explore various approaches to solve this integral, including numerical evaluation and potential transformations into complex functions.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant expresses uncertainty about the value of the integral and seeks assistance.
  • Another participant questions the classification of the integral as a complex line integral and suggests finding a complex function that matches the integrand on the unit circle.
  • A different participant proposes various complex functions, such as \(e^z\) and \(ze^{z}\), and encourages experimentation with these to approach the solution.
  • One participant claims that the integral evaluates to zero if \(n\) is odd and provides a formula for even \(n\), though they express uncertainty about how to prove this result.
  • Another participant reiterates that the integral equals zero for integer \(n\) but notes that it is specifically zero for odd integers and not for even integers, suggesting numerical methods for non-integer values.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the evaluation of the integral. There are competing views regarding the behavior of the integral based on the parity of \(n\) and the methods for solving it.

Contextual Notes

Some participants mention numerical evaluations and reference specific mathematical resources, indicating that there may be limitations in the analytical approach or unresolved steps in the evaluation process.

burak100
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find the value,

[itex]\int\limits_{0}^{2\Pi} e^{-\sin t} \sin\lbrace (\cos t ) - (n-1) t \rbrace dt[/itex] ?

I have no idea...
 
Last edited:
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Well, since you title this "complex line integral 2" but there is no complex line integral in the problem, did you consider converting it to one? Can you find complex function that reduces to that integrand on the unit circle in the complex plane?
 
integral

I can't find

[itex]\int\limits_{0}^{2\Pi} e^{-\sin t} \sin\lbrace (\cos t ) - (n-1) t \rbrace dt[/itex] ?
 
burbak . . . remove that other one. Need to just try things and these things lead you to other things and sometimes they lead you to the solution. Tell you what, how about . . . I don't know, say e^z? What happens if I consider:

[tex]\oint_{|z|=1} e^z dz[/tex]

and I let z=e^{it} and convert that all to sines and cosines? What's it look like? Close huh? One of the most important things I can tell you about succeeding in math is just get it close to start. See, that's it! Ok, say e^{iz}. What about that? What's that look like? Better? How about ze^{z}? Again, convert it all to sines and cosines. We makin' progress I think. How about z^2e^{iz}. Again, turn the crank. Then maybe e^{z}/z or e^{z}/(z^2). What's that look like? Now here's what to do. You try one or a few of theses and then report back what you found. That way it looks like you're trying and others will be motivated to help you further.
 
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Interesting! From evaluating this integral numerically, it is clear that it is equal to zero if n is odd, and it is equal to:
[tex]\frac{2\pi (-1)^\frac{n+2}{2}}{(n-1)!}[/tex]
if n is even. However, I don't see a way to show this. Does anyone?
 


The integral = 0 if n is an integer. Otherwise, you'll probably have to do it numerically. Gradshteyn & Ryzhik 3.936.2 is a near miss.
 


obafgkmrns said:
The integral = 0 if n is an integer. Otherwise, you'll probably have to do it numerically. Gradshteyn & Ryzhik 3.936.2 is a near miss.

It's only zero for odd integers. If you plot it, you'll see that it is clearly not zero for even integers.
 
Moderator's note: merged two threads created by duplicate posts.
 

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