- #1
Sneakatone
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a(n) proton (mass 1.67x10^-27 kg) of kenetic energy 1.58x10^-12 J is moving toward a(n) proton (mass 1.67x10^-27) at rest. what is the velocity of the center of mass of the system
I used the equation k=1/2mv^2 -> sqrt(2k/m)=v
sqrt(2*1.58x10^-12 /1.67x10^-27)=4.34x10^7
I used the equation k=1/2mv^2 -> sqrt(2k/m)=v
sqrt(2*1.58x10^-12 /1.67x10^-27)=4.34x10^7