What is the Velocity of the Third Object After Explosion?

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The problem involves an object that explodes into three equal masses, with one mass moving east at 15.0 m/s and another at 10.0 m/s at a 45-degree angle south of east. Since the object exploded from rest, the total momentum before the explosion is zero, meaning the momentum after the explosion must also equal zero. To find the velocity of the third object, conservation of momentum principles must be applied, taking into account the vector components of the known velocities. The discussion emphasizes the importance of understanding momentum conservation in this scenario, particularly given the absence of friction. The solution hinges on calculating the third mass's velocity to ensure total momentum remains balanced.
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Homework Statement


An object explodes into 3 equal masses. One mass moves east at a velocity of
15.0 m/s . If a second mass moves at a velocity of 10.0 m/s 45degrees south of east.
What is the velocity of the 3rd object


Homework Equations


I know m1 = m2 = m3 therefore we have just M


The Attempt at a Solution



I have no idea where to start ... can anyone help me get started at least??
 
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Momentum has to be conserved from the Center of mass but you were never given an initial velocity I don't think you can solve it?

EDIT: Did the object explode form rest?
 
yes it exploded from rest, and my teacher said in this case there is no friction ...
 
VanKwisH said:
yes it exploded from rest, and my teacher said in this case there is no friction ...

Momentum has to be conserved for the center of mass of the individual particles, which equaled 0 before the explosion, can you see where to go form here?
 
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