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What is the velocity?

  1. Mar 13, 2010 #1
    1. The problem statement, all variables and given/known data

    A man jumps on a trampoline with an angle of 53[tex]\circ[/tex] with respect to the horizontal. What velocity does he need in order to be caught by the other man who is 5.2 m away from him, and 6.1 m above the ground?

    2. Relevant equations

    so I guess...

    X= 5.2 m
    Y= -6.1 m

    am I correct?


    3. The attempt at a solution

    So far, the only thing I've actually understood is..

    Vix = Vxcos30[tex]\circ[/tex]
    Viy = Vysin30[tex]\circ[/tex]

    Can someone please guide me through this?
     
  2. jcsd
  3. Mar 14, 2010 #2

    ehild

    User Avatar
    Homework Helper
    Gold Member

    What do you know about projectile motion ? Why do you use 30° angle? What is Vx, Vy?

    ehild
     
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