What is the volume and area determined by three points?

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Homework Help Overview

The problem involves determining the area and volume defined by three points in three-dimensional space, specifically focusing on vectors derived from these points. The original poster presents calculations for the area of a rectangle and the volume of a tetrahedron formed by these vectors.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the correctness of the original poster's approach, questioning the assumption that the vectors determine a rectangle and suggesting the use of cross and dot products for area and volume calculations. Some participants clarify the definitions of geometric shapes involved, such as parallelograms and rectangular prisms.

Discussion Status

The discussion is active, with participants providing feedback on the original calculations and suggesting alternative methods for determining area and volume. There is an acknowledgment of the need for corrections and improvements, particularly regarding the geometric interpretations of the vectors.

Contextual Notes

Some participants highlight the importance of using specific mathematical relations, such as those involving the cross product and dot product, to accurately solve the problems presented. There is an ongoing exploration of the implications of the vectors not being orthogonal.

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Homework Statement


Let P = (2, 2, 0), Q = (0, 4, 1) and R = (-1, 2, 3) in the space [tex]\Re^{3}.[/tex]
a) Determine the area of the rectangle determined by vectors [tex]\overrightarrow{PQ}[/tex] and [tex]\overrightarrow{PR}[/tex].
b) Determine the volume of the tetrahedral determined by vectors [tex]\overrightarrow{PQ}[/tex] and [tex]\overrightarrow{PR}[/tex], and the origin O, OPQR.

The Attempt at a Solution


a)
[tex] |\overrightarrow{PQ}| = \sqrt {4 + 4 +1} = 3[/tex]

[tex] |\overrightarrow{PR}| = \sqrt {9 + 0 + 9} = 3 \sqrt {2}[/tex]

[tex] Area = |\overrightarrow{PQ}| * |\overrightarrow{PR}|<br /> = 9 \sqrt {2}[/tex]

b)
[tex] Volume = Area * |\overrightarrow{RO}|<br /> |\overrightarrow{RO}| = \sqrt {1 + 4 + 9} <br /> = \sqrt {14}[/tex]

The volume is
[tex] Volume = 9 \sqrt{2} * \sqrt {14}<br /> = 18 \sqrt {7}[/tex]

Please, comment any mistakes.
 
Last edited:
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PR and PQ are not orthogonal, they don't determine a rectangle. Ditto for the second problem. You should be using the cross product and the dot product to solve these problems. Do you know any relations between them and the area and volume?
 
If you mean "parallelogram" and "rectangular prism", then the area of the parallelogram determined by the two vectors [itex]\vec{u}[/itex] and [itex]\vec{v}[/itex] is given by [itex]\vec{u}\times\vec{v}= |u||v|sin(\theta)[/itex] while the rectangular prism determined by the three vectors [itex]\vec{u}[/itex], [itex]\vec{v}[/itex], and [itex]\vec{w}[/itex] has volume [itex]\vec{u}\cdot(\vec{v}\times\vec{w})[/itex].
 
Dick said:
PR and PQ are not orthogonal, they don't determine a rectangle. Ditto for the second problem. You should be using the cross product and the dot product to solve these problems. Do you know any relations between them and the area and volume?

You are right. We need to use Sarrus.
The b -part changes to:

b)
[tex] Volume = Area * |\overrightarrow{PQ} x \overrightarrow{PR}|[/tex]

[tex] \overrightarrow{PQ} x \overrightarrow{PR} = (6, 3, 6) // by Sarrus[/tex]

[tex] |\overrightarrow{PQ} x \overrightarrow{PR}| = 9[/tex]

The volume is
[tex] Volume = 9 \sqrt{2} * 9<br /> = 81 \sqrt {2}[/tex]

Please, suggest any improvements.
 
HallsofIvy said:
If you mean "parallelogram" and "rectangular prism", then the area of the parallelogram determined by the two vectors [itex]\vec{u}[/itex] and [itex]\vec{v}[/itex] is given by [itex]\vec{u}\times\vec{v}= |u||v|sin(\theta)[/itex] while the rectangular prism determined by the three vectors [itex]\vec{u}[/itex], [itex]\vec{v}[/itex], and [itex]\vec{w}[/itex] has volume [itex]\vec{u}\cdot(\vec{v}\times\vec{w})[/itex].

I mean parallelogram.
Thank you for the correction!
 

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