What is the Wavelength of Scattered Radiation in a Compton Effect Experiment?

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In a Compton effect experiment using x-rays with a wavelength of 4.5*10^-12 m scattered at an angle of 53 degrees, the wavelength of the scattered radiation is calculated to be 5.47*10^-12 m. The relevant formula for determining the change in wavelength is Δλ = h/mc * (1 - cosθ), where h is Planck's constant and m is the mass of the electron. A common mistake involves misapplying the formula, leading to confusion about whether to add or subtract the initial wavelength from the change in wavelength. The correct approach is to add the change in wavelength to the initial wavelength to find the final wavelength. Understanding these calculations is crucial for accurately interpreting results in Compton scattering experiments.
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Homework Statement



If x ray with a weavelength of 4.5*10^-12m are used in a Compton effect experiment and are scattered at an anlge of 53.0 degree, the wavelength of the scattered radiation is?

ANS: 5.47*10^-12

Homework Equations





The Attempt at a Solution



The only thing i could think of was Δλ=h/mc*(1-cosθ)
which doesn't work seeing as how the xray didnt impact anything, i even tried it as if it impaced an electron using the mass of the electron. What formula or concept am i missing?
 
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skg94 said:

Homework Statement



If x ray with a wavelength of 4.5*10^-12m are used in a Compton effect experiment and are scattered at an anlge of 53.0 degree, the wavelength of the scattered radiation is?

ANS: 5.47*10^-12

Homework Equations



The Attempt at a Solution



The only thing i could think of was Δλ=h/mc*(1-cosθ)
which doesn't work seeing as how the x-ray didn't impact anything, i even tried it as if it impacted an electron using the mass of the electron. What formula or concept am i missing?
In Compton scattering, the x-rays are usually scattered by electrons.

With that, I get the given answer.
 
Last edited:
skg94 said:

Homework Statement



If x ray with a weavelength of 4.5*10^-12m are used in a Compton effect experiment and are scattered at an anlge of 53.0 degree, the wavelength of the scattered radiation is?

ANS: 5.47*10^-12

Homework Equations





The Attempt at a Solution



The only thing i could think of was Δλ=h/mc*(1-cosθ)
which doesn't work seeing as how the xray didnt impact anything, i even tried it as if it impaced an electron using the mass of the electron. What formula or concept am i missing?

For m did you use the rest mass of the electron? 'Cause the formula is correct.
 
I did

6.63*10^-34/ 9.11*10^31 * 3*10^8 * (1-cos53)= 9.65959164*10^-13

Then ANS - 4.5*10^-12 which yields 3.53*10^-12.

what did i do wrong?
 
skg94 said:
I did

6.63*10^-34/ 9.11*10^31 * 3*10^8 * (1-cos53)= 9.65959164*10^-13

Then ANS - 4.5*10^-12 which yields 3.53*10^-12.

what did i do wrong?
How about ANS + 4.5*10^-12 ?
 
SammyS said:
How about ANS + 4.5*10^-12 ?

oh, how come its plus isn't Δλ= λi-λf, or is it plus? isn't the change in something usually subtract?
 
skg94 said:
oh, how come its plus isn't Δλ= λi-λf, or is it plus? isn't the change in something usually subtract?
You start with λi and finish with λf , so λi + Δλ = λf . In other words, Δλ = λf - λi , like with anything else.
 
ah.. silly mistakes are the ones that always get you thank you
 
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