What is the x>0 mean here? standing wave equation find nodes?

AI Thread Summary
The discussion centers on finding the positions of the first two nodes in a standing wave described by the equation y = 2sin(31.42x)cos(7854t). A node is defined as a point where the wave displacement is always zero, which occurs when 2sin(31.42x) = 0. Participants express confusion over the lack of information regarding the starting point of the wave and the range of x. To find nodes, it is necessary to solve for x values that satisfy the equation, while antinodes occur where the amplitude is at a maximum. Clarification is sought on the implications of x being greater or less than zero in relation to nodes and antinodes.
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Homework Statement


Two waves travel in opposite direction form a standing wave of y= 2sin(31.42x)cos(7854t).
Find the positions of first two nodes with x>0.


Homework Equations





The Attempt at a Solution


The question didn't say whether the standing wave starts from node or antinode . The question didn't say how long is x, even I know the wavelength and frequency also don't know how to calculate, how? Please help
 
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Outrageous said:

Homework Statement


Two waves travel in opposite direction form a standing wave of y= 2sin(31.42x)cos(7854t).
Find the positions of first two nodes with x>0.


Homework Equations





The Attempt at a Solution


The question didn't say whether the standing wave starts from node or antinode . The question didn't say how long is x, even I know the wavelength and frequency also don't know how to calculate, how? Please help

Tell me what 'node' means.
 
Dick said:
Tell me what 'node' means.

The point that is not moving in standing wave. X=0. Then t= 0 ,then I will get first node, the second node, t=2?

Thanks
 
Outrageous said:
The point that is not moving in standing wave. X=0. Then t= 0 ,then I will get first node, the second node, t=2?

Thanks

No, a node is a point where y=0 for all values of t. Try to find the first two value of x that satisfy 2sin(31.42x)=0.
 
Yup, y=0, thank you very much
 
Then for antinode position is dy/dT= 0 ? The amplitude is maximum for all kind of y.
 
The position of the first two antinode s with x< 0. X<0 here mean they want the x value be negative , if I use, dy/dt = 0, then I will get sin34.42x= 0 , how to make x become less than zero here? Please thanks
 
Outrageous said:
The position of the first two antinode s with x< 0. X<0 here mean they want the x value be negative , if I use, dy/dt = 0, then I will get sin34.42x= 0 , how to make x become less than zero here? Please thanks

Antinode is where the amplitude reaches a maximum as a function of x. To find maxima you want to use calculus and solve dy/dx=0.
 
Why I can't use dy/dT=0? Is that because x<0? What does that mean ? please .
 
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