What is the Young's modulus of a nylon rope used for climbing?

AI Thread Summary
To calculate the Young's modulus of a nylon rope used for climbing, the elongation of the rope under load must be considered. The rope is 41m long, with a diameter of 0.4 cm, and it elongates 1.8m when supporting a 97kg climber. The Young's modulus can be determined using the formula that relates stress and strain, incorporating the rope's dimensions and the applied force due to the climber's weight. The possible answers provided include values ranging from 25 x 10^6 Pa to 86 x 10^6 Pa. Proper calculations and adherence to forum rules regarding homework assistance are necessary for clarity and effective responses.
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Homework Statement




For safety climbing, a mountaineer uses a nylon rope that is 41m long and 0,4 cm in diameter. When supporting a 97kg climber, the rope elongates 1,8m. Find its Young’s modulus. The acceleration of gravity is 9,8 m/s2

a) 82,46 x 108 Pa
b) 17,18 x 108 Pa
c) 25 x 106 Pa
d) 86 x 10 6 Pa


Homework Equations





The Attempt at a Solution

 
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Last edited:
Pietro, please use one thread per HW problem. This cuts down on the confusion when folks want to reply to your posts.

Also, you must show an attempt at solution of your HW problem per the forum rules.
 
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