yungman
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I am confuse with this:
Let\;\; t=jx \;\;,\;\; j =\sqrt{-1}
\Rightarrow \frac{dt}{dx}=j
But if I use t^2=-x^2 \;\Rightarrow\; 2t\frac{dt}{dx}=-2x
\Rightarrow \frac{dt}{dx}=-\frac{x}{t}
What is wrong?
Let\;\; t=jx \;\;,\;\; j =\sqrt{-1}
\Rightarrow \frac{dt}{dx}=j
But if I use t^2=-x^2 \;\Rightarrow\; 2t\frac{dt}{dx}=-2x
\Rightarrow \frac{dt}{dx}=-\frac{x}{t}
What is wrong?