What Mechanism Explains the Rate Law for 2A + B2 -> 2AB?

AI Thread Summary
The discussion centers on determining a reaction mechanism for the equation 2A + B2 -> 2AB, given the rate law Rate = k[A][B2]. A proposed mechanism suggests that the reaction involves an initial step where A reacts with B2 to form AB and B, followed by a second step where B reacts with A to produce more AB. The reasoning indicates that the slow steps of the mechanism involve one mole of A and one mole of B2, aligning with the rate law. The participant expresses a need for guidance due to a lack of understanding after being absent. Overall, the focus is on developing a coherent mechanism that fits the provided rate law.
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Homework Statement



"Given the rate law for the following equation is Rate = k[A][B2]
2A + B2 ------> 2AB

Suggest a mechanism for the reaction


Homework Equations



I have no clue; I was absent for 2 weeks and now have to teach myself the first two units, I've been able to teach myself rate law and order of the reaction and equilibrium stuff but I am lost on this.

The Attempt at a Solution



A + B = AB
AB + AB = 2AB

Any guidance would be nice.
 
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I'm also a student but I'm going to try this, since the rate law stated that Rate = k[A][B2] so my assumption is

A + B2 ---> AB + B
B + A ----> AB

since the rate law is Rate = k[A][B2] it should means that the slow steps consist of 1 mol of A and 1 mol of B2
 
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