What points is the tangent line of curve paralell to a vector?

kelp
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Homework Statement


4x^2 - xy + y^2 = 4
At what points is the tangent line to the above curve vector [1 1]T? (T means I transposed the vector)


Homework Equations





The Attempt at a Solution


I have the gradient vector, but I'm conceptually lost about what to do after that.
 
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How can the tangent line be a vector? Do you mean that the vector (1,1) is parallel to the tangent line? If so, just use implicit differentiation, substitute the appropriate value for dy/dx, and solve.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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