What self-induced emf appears in that coil?

  • Thread starter Thread starter McAfee
  • Start date Start date
  • Tags Tags
    Coil Emf
AI Thread Summary
The discussion focuses on calculating self-induced electromotive force (emf) in a coil using the formula involving inductance and current. The user correctly identifies the units as nanoweber (nWb) but expresses confusion over the calculation, specifically the division by the number of turns. Clarification is sought regarding the relationship between mutual inductance and the number of turns in the coil. The formula for mutual inductance is highlighted, emphasizing the need to understand the role of turns in the calculation. The conversation underscores the importance of correctly applying the principles of inductance in solving the problem.
McAfee
Messages
96
Reaction score
1

Homework Statement


QJ5aY.png




The Attempt at a Solution



I now know the units are nWb. I'm just getting a little confused by answer.

((6.1mH)(7.3mA))/224turnes=.198795) (mH*mA)/turnes

So would that equal= 198.795 nWb?
 
Physics news on Phys.org
McAfee said:
I now know the units are nWb. I'm just getting a little confused by answer.

((6.1mH)(7.3mA))/224turnes=.198795) (mH*mA)/turnes

So would that equal= 198.795 nWb?

Why are you dividing by the number of turns? From the definition of mutual inductance,
$$M = \frac{\Phi_2}{I_1}$$
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Induced EMF in a coil outside a solenoid
Replies
15
Views
7K
Calculating the EMF in the coil while the field is changing
Replies
6
Views
2K
Induced EMF graph of a very small wire moving through a coil
Replies
3
Views
2K
Finding Induced EMF of secondary coil
Replies
1
Views
1K
Inductive charging: Emf induced in two coil loops
Replies
4
Views
2K
Time constant of an inductor coil
Replies
17
Views
2K
Calculating Average EMF in Two Coils on a Ferromagnetic Core
Replies
7
Views
3K
What is the amplitude of induced EMF in a magnetic dipole antenna?
Replies
3
Views
2K
Flux and Induced EMF vs displacement graphs
Replies
7
Views
5K
B EMF induced by Bar Magnet falling through a Coil
Replies
3
Views
544

Hot Threads

Recent Insights

Back
Top