What Should Be Written for x3 in a Homogeneous System When x1 and x2 are Zero?

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Homework Statement


Solve the homogeneous system of equations.

Homework Equations


The relevant matrix is like so:
1 0 0
-1 0 0
3-5 0

The Attempt at a Solution


Add R1 to R2, then add -3R1 to R3.

1 0 0
0 0 0
0-5 0

Interchange R2 and R3, then divide the new R2 by -1/5

1 0 0
0 1 0
0 0 0

Under other circumstances where there's a general solution to such a matrix, with a row of zeroes on the bottom, but not an empty column for x3, you would write x3=r or what have you and then include r when solving for x1 and x2. In this case, where x1 and x2 simply equal zero, what would one write about x3?
 
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MoreDrinks said:

Homework Statement


Solve the homogeneous system of equations.


Homework Equations


The relevant matrix is like so:
1 0 0
-1 0 0
3-5 0


The Attempt at a Solution


Add R1 to R2, then add -3R1 to R3.

1 0 0
0 0 0
0-5 0

Interchange R2 and R3, then divide the new R2 by -1/5

1 0 0
0 1 0
0 0 0

Under other circumstances where there's a general solution to such a matrix, with a row of zeroes on the bottom, but not an empty column for x3, you would write x3=r or what have you and then include r when solving for x1 and x2. In this case, where x1 and x2 simply equal zero, what would one write about x3?
x3 is arbitrary, meaning it can have any value.
 
In this case, you still have to set ##x_3 = r## for some ##r \in \mathbb{R}##.
 
Mark44 said:
x3 is arbitrary, meaning it can have any value.

Karnage1993 said:
In this case, you still have to set ##x_3 = r## for some ##r \in \mathbb{R}##.

Thank you both.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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