What should I do when faced with a mixture of real and complex eigenvalues?

[Mindscrape]

I need to solve the differential equation
\mathbf{x&#039;} = \left( <br /> \begin{array}{ccc}<br /> 3 &amp; 0 &amp; -1\\<br /> 0 &amp; -3 &amp; -1\\<br /> 0 &amp; 2 &amp; -1<br /> \end{array}<br /> \right) \mathbf{x}

solving for the eigenvalues by taking the determinate and using the "basketweave" yields

(3 - \lambda)(-3-\lambda)(-1-\lambda) + 2(3-\lambda) = 0

and further simplification shows that

-\lambda^3 - \lambda^2 +7\lambda +15 = 0

guessing roots, I found that 3 is one and divided the polynomial by the root

(\lambda - 3)(-\lambda^2 - 4\lambda -5)=0

so the eigenvalues are (solving for both eqns in the brackets)
\lambda = 3
\lambda = 2 + i
\lambda = 2 - i

The thing is that when I put in the real eigenvalue, it doesn't seem to have an eigenvector. Is this right? I think it would be because I don't have any idea how to get the solution for a mixture of real and complex eigenvalues. The solutions I know how to solve are when the eigenvectors are of the form v1,v2=p±iq. Though I imagine that if the real eigenvalue made an eigenvector I could just take the general solution of that and add it to the general solution of the complex eigenvectors.

Basically what I want to know is, what do I do know?

 

[qbert]

there's some miscalculation there.
eigenvalues are 3, (-2 + i), (-2 -i)

you can just look at the matrix and
pick the eigenvector that gives 3 as
the eigenvalue. (1, 0, 0).