What Triggers Current Flow in a Photo-Tube?

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When violet light strikes a negative electrode in a photo-tube, it initiates a current flow. Blue light, infrared radiation, and ultraviolet radiation are all forms of electromagnetic radiation that can potentially cause a current to flow, depending on their energy and wavelength. Blue light is likely to produce a stronger current than infrared due to its higher energy and shorter wavelength. The arrangement of these radiations by increasing energy per photon indicates that ultraviolet light has more energy than violet light, while infrared has less. Understanding the specific characteristics of each type of radiation is crucial for predicting their effects on current flow in the photo-tube.
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I am having trouble answering this question.

When violet light is beamed onto a negative electrode in a photo-tube, a current begins to flow in the tube. Consider the following forms of electric radiation : Blue Light; infrared radiation; ultraviolet radiation. Which of these must also cause a current to flow in the tube, provided all other conditions remain the same?

I was stuck between Blue light and all three. I don't know which it is.
 
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Arrange the radiations in the order of increasing energy per photon (increasing frequency). Which, if any, has at least as much energy as the violet light?
 


Based on the information given, it is likely that all three forms of electric radiation (blue light, infrared radiation, and ultraviolet radiation) would cause a current to flow in the photo-tube. This is because all three forms of radiation are forms of electromagnetic radiation, which can interact with the electrons in the photo-tube and cause a current to flow. However, the intensity and wavelength of the radiation may affect the strength of the current. For example, blue light may cause a stronger current compared to infrared radiation due to its higher energy and shorter wavelength. Therefore, it is important to consider the specific conditions and characteristics of the radiation when determining its effect on the current in the photo-tube.
 
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