B What use is there for rationalizing denominator?

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Rationalizing the denominator is a technique used primarily to simplify expressions involving radicals, making it easier to perform calculations without a calculator. The discussion highlights that dividing an irrational number by a rational number is often more straightforward, especially in manual calculations. Additionally, this method is applicable to complex numbers, where multiplying by the complex conjugate simplifies the expression. The participants also touch on formatting math equations in forum posts, noting preferences for using LaTeX for clarity. Overall, while rationalizing may seem unnecessary at times, it serves practical purposes in algebra and complex number operations.
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I've been learning algebra for the past 2 years (in high school), not once have we ever had to rationalize a denominator in a radical expression. I am now relearning Algebra and Trig., what use is there? I mean, all you're doing is switching the numerator (rational) to the Denominator (irrational) in terms of rationality. (not actually switching the numbers).

Rational / Irrational → Irrational / Rational
 
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After quite a while of thinking about this, the only conclusion I can come up with is to simplify it.

Say for example, 6 / √12 → 6√3 / √(12 ⋅ 3) → 6√3 / 6 → √3
 
leighflix said:
I've been learning algebra for the past 2 years (in high school), not once have we ever had to rationalize a denominator in a radical expression. I am now relearning Algebra and Trig., what use is there? I mean, all you're doing is switching the numerator (rational) to the Denominator (irrational) in terms of rationality. (not actually switching the numbers).

Rational / Irrational → Irrational / Rational
The main rationale behind this technique is that it's easier to divide an irrational number by a rational number than the other way around, especially if you don't have a calculator or computer to do the work for you.

The technique is also used for fractions that involve complex numbers. For example, ##\frac 1 i## can be simplified by multiplying by the complex conjugate over itself; i.e., by multiplying by ##\frac{-i}{-i}## (which is 1). So ##\frac 1 i = \frac 1 i \cdot \frac{-i}{-i} = \frac{-i}{1} = -i##.
 
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Thanks, and a small side question: How do you create the fractions? (on this forum)
 
Regarding the format of math equations: If you see an example math equation here whose format you want to mimic, you can right-click and see the Show Math As => TeX commands. Copy it and surround it with [ tex] ... [/tex]. (Note. I had to insert a space before 'tex' to stop the formatter from parsing it). Here is an example from a post above.

\frac 1 i = \frac 1 i \cdot \frac{-i}{-i} = \frac{-i}{1} = -i
 
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FactChecker said:
Copy it and surround it with [ tex] ... [/tex].
I never use these any more -- I find it simpler to use $$ at the beginning of the expression and $$ at the end -- it's less to type. For stuff that I want to show inline, I use ## at the beginning and two more of them at the end. The ## pairs are equivalent to ....
 
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I personally consider ##\frac{1}{\sqrt{2}} + \frac{1}{\sqrt[3]{3}} = \frac{\sqrt2}{2} + \frac{\sqrt[3]9}{3} = \frac{3\sqrt2+2\sqrt[3]9}{6}## to be simpler than ##\frac{1}{\sqrt2} + \frac1{\sqrt[3]3} = \frac{\sqrt2+\sqrt[3]3}{\sqrt2 \sqrt[3]3}## but this is a YMMV thing.
 
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