What Volume Does One Mole of Ideal Gas Occupy at 300 K and 1 atm?

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SUMMARY

The volume of one mole of an ideal gas at 300 K and 1 atm is 24.1 L, as derived from the ideal gas law equation PV=nRT. The calculation involves using R = 8.314 J/(mol·K) and converting units appropriately. The incorrect initial calculation of 2494 L resulted from a misunderstanding of unit conversions for pressure. Proper unit handling is crucial for accurate results in gas law problems.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Knowledge of unit conversions for pressure (atm to Pa)
  • Familiarity with the concept of moles in chemistry
  • Basic algebra for solving equations
NEXT STEPS
  • Review unit conversions for pressure, specifically from atm to Pascals.
  • Study the Ideal Gas Law and its applications in various conditions.
  • Practice problems involving the calculation of gas volumes under different temperatures and pressures.
  • Explore the significance of the gas constant R in different units.
USEFUL FOR

Chemistry students, educators, and anyone studying thermodynamics or gas laws will benefit from this discussion.

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Homework Statement



What is the volume of one mole of ideal gas at 300 K and at standard atmospheric pressure?

a. 23.2 L
b. 24.1 L
c. 24.6 L
d. 25.7 L

Homework Equations



PV=nRT

The Attempt at a Solution



1atm*V=1mole*8.314*300K
V=2494 L

which is not in the options :s
what did I do wrong?
 
Physics news on Phys.org
You must use the correct units fo pressure
 

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