What will be the diameter of your coil?

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To determine the diameter of a coil made from a 1.10-m-long copper wire that generates a 0.800 mT magnetic field with a current of 1.50 A, the relevant equation is B = (mu_0)(n)(i)/(2r). The user attempts to relate the number of turns (n) and the radius (r) using the wire length constraint, leading to the equation nr = 1.1/2(pi). The calculations involve substituting values into the magnetic field equation and solving for r, but the user expresses uncertainty about their approach. Assistance is requested to finalize the calculations and find the correct diameter based on the given parameters.
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Homework Statement



You have a 1.10-m-long copper wire. You want to make an N-turn current loop that generates a 0.800 mT magnetic field at the center when the current is 1.50 A. You must use the entire wire.

What will be the diameter of your coil?


Homework Equations



B = (mu_0)(n)(i)/(2r)

2(pi)(r)(n) = 1.1 ?

The Attempt at a Solution



0.8 * 10^-3 = 4(pi)*(10^-7)n(1.5)/2r

find n/r from this then:

nr = 1.1/2(pi)

combine the two you get r^2 = ...

I'm not sure if I am going right here although I'm quite positive.. Need help on the calculations.
 
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ok.. if the question was this: You have a 1.0-m-long copper wire. You want to make an N-turn current loop that generates a 1.0 mT magnetic field at the center when the current is 1.0 A. You must use the entire wire.

the answer would be:

http://img10.imageshack.us/img10/8501/picture3vwq.png

now please help me find the answer that corresponds to my values.
 
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anyone?
 
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