Athyn
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What would the explosive yield of a 100kg, 1 meter long, solid core titanium rod falling to the Earth from high-orbit be?
The discussion revolves around the explosive yield of a solid core titanium rod falling to Earth from high orbit, exploring the theoretical implications of kinetic energy conversion into explosive force. Participants consider the physics involved, potential applications, and comparisons to existing weapon systems.
Participants express a range of views on the feasibility and effectiveness of the proposed weapon system, with no consensus reached on the assumptions or calculations presented. Disagreements exist regarding the practicality of the design, the physics of impact, and the comparison to existing weapon systems.
Participants highlight various assumptions about energy conversion and impact dynamics, noting that the calculations depend on specific conditions and definitions that may not be universally accepted. The discussion reflects a mix of theoretical exploration and practical considerations.
Loren Booda said:Assuming the bar's kinetic energy was converted entirely into an explosion, Earth's mass ME=6 x 1027 gm and radius RE=6 x 108 cm, and that the bar b was released from infinity, use Newton's law of gravitation:
EG=GmbME/RE.
Shooting star said:Using the above values, it comes to around 6.7*10^9 Joules. Hopefully, I haven't made any mistakes.
And Athyn, why would you want to know the answer to a scientific question if you can't plug in four values? No offence intended.
Jeff Reid said:It would mostly just penetrate the gound. Bunker busters were made from the large heavy cannons of battleships, and would simply pentrate many feet of concrete before their fuses would time out and set off the actual explosion.
Athyn said:I don't believe that it would penetrate the ground too much. The force of the impact when it hits the ground would probably obliterate it. And even if it did penetrate the ground, the kinetic force of it slamming into the ground would be immense.