When do I use this k5 Kinematic Equation

  • Thread starter Thread starter EASports555
  • Start date Start date
  • Tags Tags
    Kinematic
AI Thread Summary
The kinematic equation d = Vƒt - 0.5at^2 allows for the calculation of one unknown variable when the other three are known. The discussion highlights that the equation includes four variables: displacement (d), final velocity (Vƒ), acceleration (a), and time (t), while the initial velocity (Vi) is not part of the equation. To find the initial velocity, additional equations may be necessary. Rearranging the equation can help solve for any unknown variable if three are provided. Understanding how to manipulate the equation is crucial for solving kinematic problems effectively.
EASports555
Messages
1
Reaction score
0
Vƒ = velocity final
Vi = velocity initial
a=acceleration
t=time
0.5 = ½
^2 = squared
- = minus
d = displacement
Equation
d = t - 0.5at^2
 
Physics news on Phys.org
I look at your equation, and it has 4 variables; d, vf, a, and t.
I look at the list you have in parentheses and there are 5 variables (vi, a, vf, t, and d)
Clearly one of the variables in parentheses is not in the equation. Which one is it? That will tell you the variable that you do not have.

That seems to be the answer, but I do not see how that is going to be useful to you. Is this part of a more elaborate, or better stated problem? Are you trying to find the initial velocity? If you are, it looks like you will need some other equation.
 
EASports555 said:
Summary:: What Variable do I not have when I use this equation? ( Vi = velocity initial , a = acceleration, vf = velocity final, t = time, d= displacement)

Vƒ = velocity final
Vi = velocity initial
a=acceleration
t=time
0.5 = ½
^2 = squared
- = minus
d = displacement
Equation
d = t - 0.5at^2
With any equation you can find a single unknown quantity if you know all the others. The equation: $$d = v_ft - \frac 1 2 at^2$$ has four quantities. If you know any three, then you can calculate the fourth. This may require you to rearrange the equation. For example, if you know ##d, v_f## and ##t##, then you can find the acceleration by rearranging the equation to: $$a = \frac{2(v_ft - d)}{t^2}$$ And you can calculate ##a## by plugging in the known quantities: ##d, v_f## and ##t##.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top